Webb23 okt. 2024 · It can be represented as a straight line on a graph. The equation of the given line is y = 2x - 3. In order to find the point lying on it, consider each of the options one by one as follows, Since, LHS ≠ RHS, the given point is not the solution. Since, LHS ≠ RHS, the given point is not the solution. Since, LHS ≠ RHS, the given point is ... Webb18 aug. 2024 · Putting x = 2 , y = 3 in both sides of Equation 2x - y = 1 we get ( 2 × 2 ) - 3 = 4 - 3 = 1. So the point (2,3) satisfies the equation 2x - y = 1. Thus point (2, 3) is the solution of 2x - y = 1. So Assertion is correct. Reason : Every point lying on graph is not a solution of 2x - y = 1. We know that every point which satisfy the linear ...
7.4: Graphing Linear Equations in Two Variables
Webb12 sep. 2024 · Step-by-step explanation: Substituting the coordinates of the given point, i.e., x = 2 and y = 1, into the defining equation, we get: 2x + y = 5 (Given) 2(2) + 1 = 5. 4 + … WebbFrom a very geometric point of view, the point on the line ℓ defined by y = 2x + 4 that is closest to the origin is the point of intersection of ℓ and a line perpendicular to ℓ through the origin. Let's call this perpendicular line ℓ ⊥, just for specificity. csusb health science
Equation of a line is y = 2x. a) A is a point on the line. If the x
WebbLet y in both of the equations equal the same value. You are doing this because at the two lines' point of intersection, both lines will share the same x and y value. So, let y=1/2x+5 equal y=-2x. That means -2x = 1/2x+5 0= 5/2x +5 -5 = 5/2x -2 =x Now you now that at the point where the two lines intersect, x=-2. Webb14 juli 2024 · (a) Point A lies on the line y = 2x so it satisfies the equation of the line. y=2 (−2)=−4 Hence y coordinate of point A is -4. (b) To verify whether a circle of radius 5 centred at point A (-2, -4) passes through the point B (5, 5) it is enough to show that the distance between point A and B is 5. AB= (5+2) 2 + (5+4) 2 = 49+81 = 130 =5 WebbUsing the Cartesian coordinate system, geometric shapes (such as curves) can be described by Cartesian equations: algebraic equations involving the coordinates of the points lying on the shape. For example, a circle of radius 2 in a plane, centered on a particular point called the origin, may be described as the set of all points whose … csusb health science department