WebAnswer (1 of 2): How many terms of an AP 27, 24, and 21 should be taken so that their sum is zero? Solution: Sn = 0 = (n/2)[54+(n-1)*(-3)] = n[54+3–3n] = n[57–3n] Since n … Web14 apr. 2024 · The team fired Hextall, Burke and assistant general manager Chris Pryor on Friday after the Penguins failed to reach the playoffs for the first time in 17 years. The decision to part with the trio ...
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WebThe given AP is 27, 24, 21, .. First term of the AP = 27. Common difference = 24 − 27 = −3. Let the sum of the first x terms of the AP be 0. Sum of first x terms = x 2 … Web5 apr. 2024 · number of terms in an. A P = n 2 [ 2 a + ( n − 1) d] . Complete step-by-step answer: Series of numbers given is 21, 18, 15 …. Here in this series of AP first term is 21. We can calculate the common difference by subtracting either 21 from 18 or 18 from 15. d = 18 − 21 = 15 − 18 = − 3. So, the common difference is.
WebCLASS-10TH CBSE NCERT BOOK ARITHMETIC PROGRESSION EXAMPLE-13How many terms of the AP: 24, 21, 18, . . . must be taken so that their sum is 78? WebIf the sum of a certain number of terms of the AP 27, 24, 21, 18, …. is –30, find the last term. asked Jul 26, 2024 in Arithmetic Progression by Haifa ( 52.3k points) arithmetic progression
WebHow many terms of the AP:24,21,18.... must be taken so that their sum is 78 ? Hard Solution Verified by Toppr Given: 24,21,18,... are in A.P a=24,d=21−24=−3 Sum = 2n[2a+(n−1)d] ⇒78= 2n[2×24+(n−1)(−3)] ⇒156=n[48−3n+3] ⇒156=n[51−3n] ⇒3n 2−51n+156=0 ⇒3n 2−12n−39n+156=0 ⇒3n(n−4)−39(n−4)=0 ⇒(n−4)(3n−39)=0 ∴n=4,n= … Web30 mrt. 2024 · Transcript. Ex 9.2,4 How many terms of the A.P. 6, 11/2, 5 . are needed to give the sum 25? AP is of the form 6, 11/2, 5 . Here First term = a = 6 Common difference = d = 11/2 ( 6) = 11/2 + 6 = ( 11 + 12 )/2 = 1/2 & Sum of n terms = Sn = 25 We need to find n We know that Sn = n/2 [2a + (n 1)d] Here, Sn = 25 , a = 6 , d =1/2 Putting values 25 = …
Web13 okt. 2024 · Step-by-step explanation: The given AP is,27,24,21,.... Here first term= a=27 common difference=d=24-27=-3 Let the nth term of the AP=0 => a+ (n-1)d=0 =>27+ (n-1) (-3)=0 => (n-1)= (-27)/ (-3) => n-1=9 => n=9+1 => n=10 So, the 10th term of the AP is 0. hope it will help you. Advertisement dawin32arpit Answer: 10 please mark as brainlist answer
WebConsider the following AP: 24, 21, 18..... How many terms of this AP must be taken so that their sum is 78? [4 MARKS] Solution Formula: 1 Mark Concept: 1 Mark Application: 2 … signia 5ax rechargeableWeb29 mrt. 2024 · Given AP 24, 21, 18,………. Here, a = 24 d = 21 – 24 = –3 Also, given Sum = 78 Sn = 78 We have to find value of n Putting these values in equation Sum = 𝒏/𝟐 [𝟐𝒂+ (𝒏−𝟏)𝒅] … the psychology of scammersWebSolution The correct option is B 19 Given that AP is 27, 24, 21 … a = 27; d = 24 - 27 = -3 Sn = n 2(2a+(n−1)d) Since the sum is 0 ⇒ n 2[2×27+(n−1)(−3)] =0 ⇒ n(54−3n+3) = 0 ⇒ … signia 2x hearing aidsWeb4 mrt. 2024 · How many Terms of the AP 24 21 18 must be taken so that their Sum is 78 Class 10 Maths Chapter 5 Example 13Example 13 : How many terms of the AP : 24, 21, ... signia 10 constitution piscataway njWebQuestion From - NCERT Maths Class 10 Chapter 5 SOLVED EXAMPLES Question – 13 ARITHMETIC PROGRESSIONS CBSE, RBSE, UP, MP, BIHAR BOARDQUESTION TEXT:-How many t... signia 312 hearing aid batteriesWeb8 feb. 2024 · answered Feb 8, 2024 by Beepin (59.2k points) selected Feb 9, 2024 by KumkumBharti Best answer In the given A.P; a = 24, d = 4, Sn = 72 we have Sn = n/2 {2a + (n – 1)d} 72 = n/2 {2 (24) + (n – 1) (-4)} = 144 = n {48 – 4n + 4} ⇒ 144 = n {52 – 4n} ⇒ 144 = 52n – 4n2 ⇒ 4n2 – 52n + 144 = 0 ⇒ n2 – 13n + 36 = 0 ⇒ (n – 9) (n – 4) = 0 ∴ n = 9, 4 signia 5x hearing aidsWeb25 jul. 2024 · let first term of the AP be a1= -10 second term of the AP be a2=-7 and common difference be d. d=a2-a1 d=-7- (-10) d=-7+10 d=3 so common difference is d=3 we know that, Sum of n terms in the AP is, Sn=n/2 [2a1+ (n-1)d] 104=n/2 [2×-10 + (n-1)3] 104×2=n [-20+3n-3] 208=n [3n-23] 208=3n^2-23n 3n^3-23n-208=0 3n^2-39n+16n-208=0 … sign hundreds of tests