How many bytes would s9 9 v99 occupy

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WebSep 25, 2007 · The intent of this data type is to make it the most efficient format on any given machine, which is usually some binary format. Because of this, comp varies greatly … WebPIC S9(_) USAGE COMP-5. PIC 9(_) USAGE COMP-5. Length 1 to 4 SQL_Smallint. Length 5 to 9 SQL_Integer. Length 10 to 18 SQL_Binary ... Storage representation Numeric values; S9(1) through S9(4) S9(5) through S9(9) S9(10) through S9(18) Binary half-word (2 bytes) Binary full-word (4 bytes) Binary double-word (8 bytes)-32768 to +32767-2,147,483,648 ...

how to format a number to S9 (5)V99 ascii in .net

WebJan 8, 2003 · On the other hand, a COBOL S9 (9)V99 COMP-3 is a packed decimal field and this is 2 bytes. Let me explain why. A packed decimal field is represented as HEX digits … WebNov 28, 2024 · How many bytes would S9 9 V99 occupy? there are 9 nines. (9+1)/2 = 5 bytes. S9(6)V99. there are 8 nines (8+1)/2 = 4.5 = 5 bytes. What is 77 level used for in COBOL? Entries that specify noncontiguous data items, which are not subdivisions of other items, and are not themselves subdivided, have been assigned the special level-number 77. inclusion\u0027s jt

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WebHow many bytes will a S9(8)... prev next How many bytes will a S9(8) COMP field occupy ? more than 6 months ago by anonymous Nasir Jawed. Dell India COBOL Team Lead/ Tech … WebJun 24, 2004 · If OUT-AMT is not used in this program (and it's unlikely that it is), it is not necessarily an error as the cited comp-3 field does, in fact, occupy 9 bytes. I would have either defined it as filler, or, more accurately, defined it to match AMOUNT of IN-REC (including the COMP-3). WebHow many bytes will a S9(8)... prev next How many bytes will a S9(8) COMP field occupy ? more than 6 months ago by anonymous Nasir Jawed. Dell India COBOL Team Lead/ Tech Lead. 258. UPVOTE (0) SHARE. Show More Answers (0) POST YOUR ANSWERS. Similar questions. Hardware, Software. inclusion\u0027s jw

How may do the following definitions occupy?(a) s(3)v99 comp-3(b) s(9 …

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WebNov 21, 2024 · What is the bytes occupied by S9 9 v9 2 Comp 3? 5 bytes. Quote: There are 2 digits for each character position, except for the trailing character position, which is … Webs9 (9)v9 (9) Here v stands for assumed decimal point so it will occupy. only 18 bytes (9+9)...if instead of s9 (9)v9 (9) it is coded as. s9 (9).9 (9) then it is going to occupy 19 … inclusion\u0027s k0WebJan 2, 2024 · 03 num-2 pic s9(5)v99 comp. 03 num-3 pic s9(5)v99 comp-3. Share. Improve this answer. Follow answered Jan 3, 2024 at 0:57. Bruce Martin Bruce Martin. 10.3k 1 1 gold badge 26 26 silver badges 37 37 bronze badges. Add a comment Your Answer Thanks for contributing an answer to Stack Overflow! ... inclusion\u0027s iy

"WebSep 14, 2007 · Mainframe Interview Questions: How many bytes will S9(12)V99 COMP-3 occupy? Answer: 1) 7 2) 9 3) 8 4) 6 5) 10 : How many bytes will S9(12)V99 COMP-3 occupy: IBM Mainframe Forums-> Mainframe Interview Questions : Quick References View previous topic:: View next topic : Author Message; Lavanya_Dhushetty Warnings : 2 " - How many bytes would s9 9 v99 occupy

How many bytes would s9 9 v99 occupy

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WebJan 8, 2003 · (9)V99 means that this number is composed of 1 integral position followed by 2 decimal places. The V in the V99 is implies that there are decimal places to follow. For example: If the number... WebOn the other hand, a COBOL S9(9)V99 COMP-3 is a packed decimal field and this is 2 bytes. Let me explain why. A packed decimal field is represented as HEX digits followed by a C or D as the last HEX digit for the sign. In this case, S9 means it is a signed numeric field. The (9)V99 means that this number is composed of 1 integral position

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WebSep 5, 2010 · WS-VAR S9 (5)V99 COMP-3. will be occupying 4 bytes and the corresponding Easytrieve declaration is WS-VAR W 4 P 2 The 2 is for the 2 digits after decimal point, and the 4 still means the total 4 bytes occupied. Note that the 2 is not 2 bytes and just specifies the 2 digits after decimal point. Read more about Easytrieve variable declaration. http://computer-programming-forum.com/48-cobol/8642e0b624be51c3.htm

WebJan 17, 2013 · If this "number" is always guaranteed to have the same format: 7 digits, a decimal point and 2 more digits after the decimal, the classic way of doing this in COBOL is: 01. 02 NUM-AS-PIC PIC X (10). 03 NUM-EDITED REDEFINES NUM-AS-PIC PIC 9 (7).99. 01 NUM-DEEDITED PIC 9 (7)V99. MOVE '1234567.89' TO NUM-AS-PIC <- alpha-numeric move … WebMar 6, 2024 · 9 represents a single digit; V represents an assumed decimal place; So s9(6)V99 is a signed number with 6 digits before the decimal place + 2 after. Effect of Encoding. The encoding (characterset) used by the server determines how the sign digit is represented. For US (and UK) Ebcdic +0/-0 are { / } but they are different for German …

WebApr 14, 2024 · 9 (5)-9 (9) = 4 bytes 9 (10)-9 (18) = 8 bytes.. 9 (3)v9 (7) occupies 8 bytes but the question itself wrong COMP variable doesnt have a PIC clause bcz it already contains … WebApr 9, 2010 · Unless you need a sign-nibble for the last-byte, move the S9 (11)V99 field to a 9 (11)V99 work-field and the sign-nibble will be dropped. When signed (and I'm assuming positive), the last byte will be in the range of X'C0' through X'C9'.

WebData name length Length in COBOL 9(01) to 9(04) 2 bytes 9(05) to 9(09) 4 bytes S9(10) to S9(18) 8 bytes COMP-1:In this case the data item will be represented in one word in the floating point form the number is actually represented in hexadecimal format and is suitable for arithmetic operations. The PICTURE Clause cannot be specified for COMP-1 ...

WebAug 26, 2024 · For WS-VALC PIC S9 (3) USAGE IS COMP-3, so here we can take it as (3+1)/2 which is equal to 2bytes size. Similarly, in the 3byte variable which is WS-VALD PIC S9 (4) USAGE IS COMP-3, so here we can take it as (4+1)/2 which is equal to 2.5 (rounded off) so it will take 3bytes. 10. How to Install COBOL on MacOS? Previous Program Structure of … inclusion\u0027s kWebPIC S9(5) ZD5. ZD for zoned-decimal PIC S9(5)V99 ZD7.2 Field is 7 bytes long, PIC S9(5)V999 ZD8.3 Field is now 8 bytes, and last 3 digits are decimals PIC S9(5)V99 COMP-3 PD4.2 4 bytes long, of which last 2 digits are decimals PIC 9(5)V99 COMP-3 PK4.2 Same as above but unsigned (this is rare) PIC 9(8) COMP IB4. Integer binary (signed) YYMMDD8. inclusion\u0027s k3WebByte size = (7 + 1) / 2 = 4 PIC S9 (5)V99 COMP-3. Byte size = (5 + 2 + 1) / 2 = 4 PIC S9 (6) COMP-3. Byte size = (6 + 1) / 2 = 3.5, rounded to 4 Comp-3 fields reserve a nybble for the sign, even for "unsigned" values, so the following fields are still 4 bytes: PIC 9 (7) COMP-3. Byte size = (7 + 1) / 2 = 4 PIC 9 (6) COMP-3. inclusion\u0027s k2WebDec 9, 2024 · 01 WS-NUM PIC S9(5)V9(3) USAGE IS DISPLAY. It requires 8 bytes as sign and decimal doesn't require any byte. 01 WS-NUM PIC 9(5) USAGE IS DISPLAY. It requires 5 bytes as sign. COMPUTATIONAL / COMP Data item is stored in binary format. Here, data items must be integer. inclusion\u0027s k9WebAug 7, 2024 · S9 (9)V99 comp-3 can hold values in the range of +999,999,999.99 to -999,999,999.99. Each 2 digits takes up 1 byte of a packed decimal, with the sign taking up the high-order nybble. Upvote • 0 Downvote Add comment Report Still looking for help? Get the right answer, fast. Ask a question for free Get a free answer to a quick problem. inclusion\u0027s k5WebAug 3, 2001 · The variable PARTIAL-MESSAGE should have 14 (FILLER) + 14 (VALUE2) = 28 bytes. Adding to that, the first FILLER (4 bytes) + VALUE1 (2 bytes -- even though, if the value is 1, the supressed zero is replaced by a space) = 6 bytes. And then the entire value of PARTIAL-MESSAGE (28 bytes) for a grand total of 34 bytes for ENTIRE-MESSAGE. inclusion\u0027s k7WebJul 14, 2010 · It specifies to use a leading minus sign if the number is negative, to use five digits before the decimal place, with a comma between the thousands, a decimal point, … inclusion\u0027s k4